College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.1 - Page 527: 47

Answer

(6, -1)

Work Step by Step

Set the denominators equal to each other $\frac{x + 2}{2} - \frac{y + 4}{3} = 3$ $\frac{3(x + 2)}{6} - \frac{2(y + 4)}{6} = \frac{18}{6}$ 3(x + 2) - 2(y + 4) = 18 3x + 6 - 2y - 8 = 18 3x - 2y = 20 $\frac{x + y}{5} = \frac{x - y}{2} - \frac{5}{2}$ $\frac{2(x + y)}{10} = \frac{5(x - y)}{10} - \frac{25}{10}$ 2(x + y) = 5(x - y) - 25 2x + 2y = 5x - 5y - 25 25 = 3x - 7y 25 = 3x - 7y can also be written as 3x = 25 + 7y 3x - 2y = 20 can also be written as 3x = 20 + 2y Set them equal to one another 25 + 7y = 20 + 2y 5y = -5 y = -1 Plug y into 3x - 2y = 20 3x - 2(-1) = 20 3x + 2 = 20 3x = 18 x = 6
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