College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Summary, Review, and Test - Review Exercises - Page 585: 25

Answer

$(1,0), (4,3)$

Work Step by Step

We are given the system: $\begin{cases} x-y=1\\ 5y=x^2-1 \end{cases}$ We will use the substitution method. Solve Equation 1 for $x$ and substitute the expression of $x$ in Equation 2 to eliminate $x$ and determine $y$: $\begin{cases} x=y+1\\ 5y=(y+1)^2-1 \end{cases}$ $5y=(y+1)^2-1$ $5y=y^2+2y+1-1$ $5y=y^2+2y$ $y^2-3y=0$ $y(y-3)=0$ $y=0\Rightarrow y_1=0$ $y-3=0\Rightarrow y_2=3$ Substitute each of the values of $y$ in the expression of $x$ to determine $x$: $x=y+1$ $y_1=0\Rightarrow x_1=0+1=1$ $y_2=3\Rightarrow x_2=3+1=4$ The system's solutions are: $(1,0), (4,3)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.