College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Review Exercises - Page 510: 28



Work Step by Step

We know that $y=log_{b}x$ is equivalent to $b^{y}=x$ (where $x\gt0$, $b\gt0$, and $b\ne1$). Also, based on the definition of the common logarithm, we know that $log(x)=log_{10}x$. Therefore, $log(\frac{1}{1000})=log_{10}\frac{1}{1000}=-3$, because $10^{-3}=\frac{1}{10^{3}}=\frac{1}{1000}$.
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