## College Algebra (6th Edition)

Published by Pearson

# Chapter 4 - Summary, Review, and Test - Review Exercises - Page 510: 20

-2

#### Work Step by Step

We know that $y=log_{b}x$ is equivalent to $b^{y}=x$ (where $x\gt0$, $b\gt0$, and $b\ne1$). Therefore, $log_{5}\frac{1}{25}=-2$, because $5^{-2}=\frac{1}{5^{2}}=\frac{1}{5\times5}=\frac{1}{25}$.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.