## College Algebra (6th Edition)

We know that $y=log_{b}x$ is equivalent to $b^{y}=x$ (where $x\gt0$, $b\gt0$, and $b\ne1$). Also, based on the definition of the common logarithm, we know that $ln(x)=log_{e}x$. Therefore, $ln(e^{5})=log_{e}e^{5}=5$, because $e^{5}=e^{5}$.