Answer
$49^{\frac{1}{2}}=7$
Work Step by Step
We know that $y=log_{b}x$ is equivalent to $b^{y}=x$ (where $x\gt0$, $b\gt0$, and $b\ne1$).
Therefore, $\frac{1}{2}=log_{49}7$ can be written in exponential form as $49^{\frac{1}{2}}=7$.
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 4 - Summary, Review, and Test - Review Exercises - Page 510: 13
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