Answer
$x^{3}+4x^{2}+16x+64$
Work Step by Step
Arrange the powers...
$(x^{4}+0x^{3}+0x^{2}+0x-256)\div(x-4)$
(watch out for the missing powers)
$\begin{array}{lllllll}
\underline{4}| & 1 & 0 & 0 & 0 & -256 & \\
& & 4 & 16 & 64 & 256 & \\
& -- & -- & -- & -- & -- & \\
& 1 & 4 & 16 & 64 & 0 &
\end{array}$
$(x^{4} -256)\div(x-4)=$
$=x^{3}+4x^{2}+16x+64$
