College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.2 - Page 241: 78

Answer

$-3$

Work Step by Step

We can see from the graph that: $f(−2.5)=2$ $f(1.9)=-2$ $f(-π)=3$ $f(−3)=2$ $f(1)=−2$ $f(π)=-4$ Thus: $\sqrt {f(-2.5)-f(1.9)}-[f(-\pi)]^2+f(-3)\div$ $f(1)\times$ $f(\pi)$ $=\sqrt {2-(-2)}-(3)^2+2\div (-2)\times (-4)$, $=\sqrt 4$ $-9$ $+4=-3$
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