Answer
$-18$
Work Step by Step
We can see from the graph that: $f(-1.5)=1,f(-0.9)=1,f(\pi)=-4,f(-3)=2,f(1)=-2, f(-\pi)=3$
Thus: $\sqrt{f(-1.5)+f(-0.9)}-[f(\pi)]^2-f(-3)/f(1)\cdot f(-\pi)=\sqrt{1+0}-(-4)^2+2/-2\cdot3=\sqrt1-16+-3=1-16-3=-18$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 2 - Functions and Graphs - Exercise Set 2.2 - Page 241: 77
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