Answer
$-5$
Work Step by Step
$\frac{-b-\sqrt (b^{2}-4ac)}{2a}$
Substitute $a=2, b=9$ and $c=-5$
$\frac{-b-\sqrt (b^{2}-4ac)}{2a} $$= \frac{-9-\sqrt (9^{2}-4(2)(-5))}{2(2)}$
$= \frac{-9-\sqrt (81+40)}{4}$
$= \frac{-9-\sqrt 121}{4}$
$= \frac{-9-11}{4}$
$= \frac{-20}{4}$
$=-5$