Answer
$E=(21+i)$ volts
Work Step by Step
$I=(2-3i)$ amperes $;$ $R=(3+5i)$ ohms
Ohm's law is:
$$E=IR$$
where $I$ is the current in a circuit, $R$ is the resistance of the circuit and $E$ is the voltage of the circuit.
$I$ and $R$ are given and $E$ is to be found.
Substitute the known values into the formula:
$E=(2-3i)(3+5i)=...$
Evaluate the product:
$...=6+10i-9i-15i^{2}=...$
Substitute $i^{2}$ by $-1$ and simplify:
$...=6+10i-9i-15(-1)=...$
$...=6+10i-9i+15=...$
$...=21+i$
The voltage in the circuit is $21+i$ volts