Answer
$\sqrt -9 + \sqrt -16 = 7i$
Work Step by Step
$\sqrt a+ \sqrt b \ne \sqrt (a+b).$ So,
$\sqrt -9 + \sqrt -16 \ne \sqrt-25$
Using $\sqrt -b = i\sqrt b$
$\sqrt -9 + \sqrt -16 = $ $i\sqrt 9 + i\sqrt 16 $
$=3i+4i $
$=7i$
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