College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.4 - Page 143: 62

Answer

See below.

Work Step by Step

In order to solve such a problem we need to multiply the numerator and denominator by the denominator's conjugate. E.g.: $\frac{2+i}{1+i}=\frac{2+i}{1+i}=\frac{(2+i)(1-i)}{(1+i)(1-i)}=\frac{2-2i+i+1}{1-i+i+1}=\frac{3-i}{2}$
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