College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.2 - Page 121: 105

Answer

$125$ liters

Work Step by Step

Convert $28\%$ to a decimal as $0.28$, and set it equal to $C$ in the given formula. Then distribute and combine all the like terms, and isolate the $x$-term and divide to solve for $x$. $C=\frac{x+0.1(500)}{x+500}$ $0.28=\frac{x+50}{x+500}$ $0.28(x+500)=x+50$ $0.28x+140=x+50$ $140=0.72x+50$ $0.72x=90$ $x=125$
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