College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.2 - Page 120: 104


There will be $1$ trial; $(1,0.5)$

Work Step by Step

Set $P$ in the given formula equal to $0.95$. Multiply the denominator on both sides, and distribute all the terms and combine. Then isolate the $x$-term on one side and divide to solve. $0.5=\frac{0.9x-0.4}{0.9x+0.1}$ $0.5(0.9x+0.1)=(\frac{0.9x-0.4}{0.9x+0.1})(0.9x+0.1)$ $0.5(0.9x+0.1)=0.9x-0.4$ $(0.5)(0.9x)+(0.5)(0.1)=0.9x-0.4$ $0.45x+0.05-0.45x=0.9x-0.4-0.45x$ $0.05=0.45x-0.4$ $0.05+0.4=0.45x-0.4+0.4$ $0.05+0.4=0.45x$ $0.45=0.45x$ $x=1$
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