College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.2 - Page 120: 103

Answer

There will be $11$ trials; $(11,0.95)$

Work Step by Step

Set $P$ in the given formula equal to $0.95$. Multiply the denominator on both sides, and distribute all the terms and combine. Then isolate the $x$-term on one side and divide to solve. $0.95=\frac{0.9x-0.4}{0.9x+0.1}$ $0.95(0.9x+0.1)=(\frac{0.9x-0.4}{0.9x+0.1})(0.9x+0.1)$ $0.95(0.9x+0.1)=0.9x-0.4$ $(0.95)(0.9x)+(0.95)(0.1)=0.9x-0.4$ $0.855x+0.095=0.9x-0.4$ $0.095+0.4=0.045x-0.4+0.4$ $0.095+0.4=0.045x$ $0.495=0.045x$ $x=11$
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