College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 6 - Section 6.4 - Summary of the Conic Sections - 6.4 Exercises: 9

Answer

Hyperbola

Work Step by Step

We can see that x and y are on the power of two and one with a positive the other with a negative coefficient. Therefore the equation will be a hyperbola. This given equation can be easily transformed to the standard equation of a hyperbola: $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$ Here, it is: $\frac{x^2}{2^2}-\frac{y^2}{4^2}=1$
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