College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 6 - Section 6.4 - Summary of the Conic Sections - 6.4 Exercises - Page 619: 17

Answer

Parabola

Work Step by Step

We can see that x is squared but y is not squared, therefore the equation will be a parabola. This given equation is equivalent to: $(x-3)^2+y-9=0$ $y-9=-(x-3)^2$ Which can be easily transformed to the general equation of a vertical parabola: $y-h=a(x-k)^2$ Here, it is: $y-9=-(x-3)^2$
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