College Algebra (11th Edition)

The given equation is equivalent to: $\frac{x^2}{4}+\frac{y^2}{9}=1$ We can see, that both x and y are on the power of two, with both positive, but different coefficients . Therefore the equation will be an ellipse. This can be easily transformed into the standard equation of an ellipse: $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ Here, it is: $\frac{x^2}{2^2}+\frac{y^2}{3^2}=1$