Answer
The equation is a parabola that opens upward with vertex at $(-3, -7)$.
Work Step by Step
We are given the equation as: $y+7=4 (x+3)^2$.
The equation is in the form $(y-k)=a(x – h)^2$ which represents a parabola that opens upward with vertex at $(h,k)$.
Using the form above as guide, the given equation has $h=-3$ and $k=-7$ so the vertex is at $(-3, -7)$, and $a=4$.
Therefore we conclude that the equation is a parabola that opens upward with vertex at $(-3, -7)$.
