Answer
$-5=a+b+c$
$-14=4a-2b+c$
$-10=4a+2b+c$
Work Step by Step
$$x=ay^2+by+c$$
Substitute the point $(-5,1)$:
$$-5=a\cdot 1^2+b\cdot 1+c$$
$$-5=a+b+c$$
First equation is obtained.
Substitute the point $(-14,-2)$:
$$-14=a\cdot (-2)^2+b\cdot (-2)+c$$
$$-14=4a-2b+c$$
Second equation is obtained.
Substitute the point $(-10,2)$:
$$-10=a\cdot (2)^2+b\cdot (2)+c$$
$$-10=4a+2b+c$$
