College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 6 - Section 6.1 - Parabolas - 6.1 Exercises - Page 591: 39

Answer

$y^2=\frac{4}{3}x$

Work Step by Step

Since, the parabola is symmetric with respect to the $x-$axis, it means that the parabola is opening to the right or left side. The standard form of a horizontal parabola is given as: $y^2=4px ~~~(1)$ (when the parabola has the vertex at origin $(0,0)$) Here, the point $(3,2)$ is on the graph, so we have: $x=3; y= 2$ Now, we will plug the values of x and y in the standard form of parabola to determine the value of $p$: $(2)^2=4p \times (3)$ or, $12p=4 \implies p=\frac{1}{3}$ Thus, the equation (1) becomes: $y^2 =(4)\left(\frac{1}{3}\right) x \implies y^2=\frac{4}{3}x$
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