College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 6 - Section 6.1 - Parabolas - 6.1 Exercises - Page 591: 44

Answer

$(y-2)^2=-12 (x -1)$

Work Step by Step

Since the directrix is a vertical line $4-1=3$ units to the right of vertex it means that the parabola is horizontal and facing left and $p=-3$. The standard form of a vertical parabola vertical is given as: $(y-k)^2=4p(x-h) ~~~(1)$ Here, we have $(h,k)=(1,2)$, so $h=1; k = 2$. Now, we will plug these values in equation (1) to obtain: $(y-2)^2=(4)(-3) (x-1) \implies (y-2)^2=-12 (x -1)$
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