College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 6 - Section 6.1 - Parabolas - 6.1 Exercises - Page 591: 41

Answer

$(x-4)^2=8(y-3)$

Work Step by Step

Because the vertex and the focus have the same $x$-coordinate, it follows that the parabola has a vertical axis of symmetry. Since the focus is above the vertex and the axis of symmetry is vertical, it means that the parabola opens upward. The standard form of a vertical parabola is given as: $(x-h)^2=4p(y-k) ~~~(1)$ The directed distance (p) between the vertex and the focus is $p=5-3=2$ Here, we have $h=4; k =3$ Now, we will plug these values in equation (1) to obtain: $(x-4)^2=4 (2)(y-3) \implies (x-4)^2=8(y-3)$
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