College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 5 - Section 5.1 - Systems of Linear Equations - 5.1 Exercises - Page 486: 23

Answer

$\{(4,-2)\}$

Work Step by Step

We are given the system of equations as: $$5x+7y=6 \quad\quad \quad(1) \\ 10x-3y=46 \quad \quad(2)$$ By multiplying $-2$ to the first equation. we get an equivalent equation: $$-10x-14y=-12 \quad \quad(3)$$ Add equations $(2)$ and $(3)$ to eliminate $x$ and then solve for $y$. $$-17y=34 \implies y=-2$$ Plug $y=2$ into the first equation then solve for x to obtain: $$5x+7(-2)=6 \\ 5x-14=6 \\x=4$$ So, the solution set is $\{(4,-2)\}$.
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