College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 5 - Section 5.1 - Systems of Linear Equations - 5.1 Exercises - Page 486: 22

Answer

$\{(-1,1)\}$

Work Step by Step

We are given the system of equations as: $4x+3y=-1 ~~~(1) \\ 2x+5y=3 ~~~(2)$ By multiplying second equation by $-2$ and then second equation is equivalent to: $-4x-10y=-6 ~~~~(3)$ Add equations (1) and (3) to eliminate $x$ and then solve for $y$. $4x+3y-4x-10y=-1-6 \\ -7y=-7 \\ y=1$ Plug $y=1$ into the second equation then solve for x to obtain: $2x+(5)(1)=3 \\ 2x+5=-3 \\x=-1$ So, the solution set is $\{(-1,1)\}$.
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