College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 5 - Section 5.1 - Systems of Linear Equations - 5.1 Exercises - Page 486: 18

Answer

The solution set is $\left\{(6, 2)\right\}$.

Work Step by Step

Solve for $x$ in the second equation to obtain $x=y+4$. Since $x=y+4$, substitute $y+4$ to $x$ in the first equation to obtain: $4y=2(y+4)-4 \\ \implies 4y =2y+8-4\\ \implies4y=2y+4\\ \implies 4y-2y=4\\ \\ \implies 2y=4 \\ \implies y=2$ Plug $y=2$ into the second equation then solve for $x$ to obtain: $x-y=4 \\ \implies x-2=4\\ \implies x=4+2\\ \implies x= 6$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.