Chapter 4 - Section 4.4 - Evaluating Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 438: 83

$\approx-1.5850$

Using $\log_a b=\dfrac{\log b}{\log a}$ or the Change-Of-Base Theorem, the given expression, $ \log_{1/2} 3 ,$ evaluates to \begin{array}{l}\require{cancel} \dfrac{\log3}{\log \dfrac{1}{2}} \\\\ \approx-1.5850 .\end{array}