Answer
$\approx3.1699$
Work Step by Step
Using $\log_a b=\dfrac{\log b}{\log a}$ or the Change-Of-Base Theorem, the given expression, $
\log_2 9
,$ evaluates to
\begin{array}{l}\require{cancel}
\dfrac{\log9}{\log 2}
\\\\
\approx3.1699
.\end{array}