College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.4 - Evaluating Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 438: 100

Answer

$D$: $\ln(2)$

Work Step by Step

Using the property of logarithm: $$\ln(4x)-\ln(2x)=\ln\left(\frac{4x}{2x}\right)=\ln(2)$$ The answer is option $D$.
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