Answer
$$x=\frac{-1±i\sqrt5}{3}$$
Work Step by Step
$$x=\frac{-b ±\sqrt{b^2-4ac}}{2a}$$
$$x=\frac{-2 ±\sqrt{2^2-4(3)(2)}}{2(3)}$$
$$x=\frac{-2±\sqrt{4-24}}{6}$$
$$x=\frac{-2±\sqrt-20}{6}$$
$$x=\frac{-2±2i\sqrt5}{6}$$
$$x=\frac{-1±i\sqrt5}{3}$$
College Algebra (11th Edition)
by Lial, Margaret L.; Hornsby John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671791
ISBN 13:
978-0-32167-179-0
Chapter 1 - Test - Page 167: 5
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