College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Test - Page 167: 15

Answer

$$W=\dfrac{S-2LH}{2H+2L}$$

Work Step by Step

The given formula: $$S=2HW+2LW+2LH$$ Move $2LH$ to the left side and change the sign: $$S-2LH=2HW+2LW$$ Factor out $W$ on the right side: $$S-2LH=W(2H+2L)$$ Swap the sides: $$W(2H+2L)=S-2LH$$ Divide both sides by $2H+2L$: $$W=\dfrac{S-2LH}{2H+2L}$$
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