College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Test - Page 167: 19

Answer

Length is $200~\text{m}$ and width is $110~\text{m}$

Work Step by Step

Let the length be $L$ and width be $W$. Two times width is $20$ m bigger than length: $$L=2W-20$$ Perimeter is $620$ m: $$2L+2W=620$$ Substitute $L=2W-20$: $$2(2W-20)+2W=620$$ $$4W-40+2W=620$$ $$6W=620+40$$ $$6W=660$$ $$W=660:6=110$$ Find length: $$L=2\cdot 110-20=200$$
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