Answer
No solution.
Work Step by Step
$$\frac{12}{(x+3)(x-3)}-\frac{3}{x+3}=\frac{2}{x-3}$$
$$((x+3)(x-3))(\frac{12}{(x+3)(x-3)}-\frac{3}{x+3})=((x+3)(x-3))(\frac{2}{x-3})$$
$$12-3(x-3)=2(x+3)$$
$$12-3x+9=2x+6$$
$$21-3x=2x+6$$
$$15=5x$$
$$x=3$$
3 is an extraneous solution; there is no solution.