College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.8 - nth Roots; Rational Exponents - R.8 Assess Your Understanding - Page 79: 74


$\displaystyle \frac{9}{4}$

Work Step by Step

We simplify: $(\displaystyle \frac{8}{27})^{-2/3}=(\frac{27}{8})^{2/3}=((\frac{27}{8})^{1/3})^2=(\sqrt[3]{\frac{27}{8}})^{2}=(\frac{3}{2})^{2}=\frac{9}{4}$
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