College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.8 - nth Roots; Rational Exponents - R.8 Assess Your Understanding - Page 79: 52


$\displaystyle \frac{-\sqrt{6}}{4}$

Work Step by Step

We rationalize the denominator: $\displaystyle \frac{-\sqrt{3}}{\sqrt{8}}=\frac{-\sqrt{3}\sqrt{8}}{\sqrt{8}\sqrt{8}}=\frac{-\sqrt{24}}{8}=\frac{-\sqrt{4*6}}{8}=\frac{-2\sqrt{6}}{8}=\frac{-\sqrt{6}}{4}$
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