College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.8 - nth Roots; Rational Exponents - R.8 Assess Your Understanding - Page 79: 70


$\displaystyle \frac{1}{64}$

Work Step by Step

We simplify: $\displaystyle 16^{-3/2}=((16)^{1/2})^{-3}=((4^2)^{1/2})^{-3}=4^{-3}=\frac{1}{4^3}=\frac{1}{64}$
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