Answer
$\displaystyle \frac{1}{64}$
Work Step by Step
We simplify:
$\displaystyle 16^{-3/2}=((16)^{1/2})^{-3}=((4^2)^{1/2})^{-3}=4^{-3}=\frac{1}{4^3}=\frac{1}{64}$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter R - Section R.8 - nth Roots; Rational Exponents - R.8 Assess Your Understanding - Page 79: 70
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