College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.8 - nth Roots; Rational Exponents - R.8 Assess Your Understanding - Page 79: 60


$\displaystyle \frac{-2\sqrt[3]{3}}{3}$

Work Step by Step

We rationalize the denominator: $\displaystyle \frac{-2}{\sqrt[3]{9}}=\frac{-2*\sqrt[3]{9}*\sqrt[3]{9}}{\sqrt[3]{9}*\sqrt[3]{9}*\sqrt[3]{9}}=\frac{-2*\sqrt[3]{81}}{9}=\frac{-2*\sqrt[3]{27*3}}{9}=\frac{-2*3\sqrt[3]{3}}{9}=\frac{-2\sqrt[3]{3}}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.