College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.7 - Rational Expressions - R.7 Assess Your Understanding - Page 71: 50


$\displaystyle \frac{x(5x+1)}{(x-4)(x+3)}$

Work Step by Step

$\displaystyle \frac{3x}{x-4}+\frac{2x}{x+3}=... \quad LCD=(x-4)(x+3)$ $=\displaystyle \frac{3x(x+3)+2x(x-4)}{(x-4)(x+3)}$ $=\displaystyle \frac{3x^{2}+9x+2x^{2}-8x}{(x-4)(x+3)}$ $=\displaystyle \frac{5x^{2}+x}{(x-4)(x+3)}$ $=\displaystyle \frac{x(5x+1)}{(x-4)(x+3)}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.