Answer
$\dfrac{3}{5x}; x \ne 0. \frac{9}{2}$
Work Step by Step
Factor each polynomial completely to obtain:
$=\dfrac{3(2x-9)}{5(x)} \cdot \dfrac{2}{2(2x-9)}$
Cancel the common factors to obtain:
$\require{cancel}
\\=\dfrac{3\cancel{(2x-9)}}{5(x)} \cdot \dfrac{\cancel{2}}{\cancel{2}\cancel{(2x-9)}}
\\=\dfrac{3}{5x}; x \ne 0, \frac{9}{2}$
