College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.7 - Rational Expressions - R.7 Assess Your Understanding - Page 71: 24


$\dfrac{3}{5x}; x \ne 0. \frac{9}{2}$

Work Step by Step

Factor each polynomial completely to obtain: $=\dfrac{3(2x-9)}{5(x)} \cdot \dfrac{2}{2(2x-9)}$ Cancel the common factors to obtain: $\require{cancel} \\=\dfrac{3\cancel{(2x-9)}}{5(x)} \cdot \dfrac{\cancel{2}}{\cancel{2}\cancel{(2x-9)}} \\=\dfrac{3}{5x}; x \ne 0, \frac{9}{2}$
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