College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.7 - Rational Expressions - R.7 Assess Your Understanding - Page 71: 39

Answer

$\dfrac{x^2-4}{2x-3}; x \ne \frac{3}{2}$

Work Step by Step

The expressions are similar so subtract the numerators and copy the denominator to obtain: $=\dfrac{x^2-4}{2x-3}; x \ne \frac{3}{2}$ ($x$ cannot be $\frac{3}{2}$ as it makes the expression undefined.)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.