College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.7 - Rational Expressions - R.7 Assess Your Understanding - Page 71: 40


$\dfrac{3x^2-9}{2x-1}; x \ne \frac{1}{2}$

Work Step by Step

The expressions are similar so subtract the numerators and copy the denominator to obtain: $=\dfrac{3x^2-9}{2x-1}; x \ne \frac{1}{2}$ ($x$ cannot be $\frac{1}{2}$ as it makes the expression undefined.)
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