Answer
$(x-1)(x+8)$
Work Step by Step
RECALL:
A trinomial of the form $x^2+bx+c$ can be factored if there are integers $d$ and $e$ such that $c=de$ and $b=d+e$.
The trinomial's factored form will be:
$x^2+bx+c=(x+d)(x+e)$
The given trinomial has $b=7$ and $c=-8$.
Note that $-8=(-1)(8)$ and $7=(-1)+8$.
This means that $d=-1$ and $e=8$
Thus, the factored form of the trinomial is:
$=[x+(-1)] (x+8)
\\=(x-1)(x+8)$
