Answer
$(x-16)(x-1)$
Work Step by Step
RECALL:
A trinomial of the form $x^2+bx+c$ can be factored if there are integers $d$ and $e$ such that $c=de$ and $b=d+e$.
The trinomial's factored form will be:
$x^2+bx+c=(x+d)(x+e)$
The given trinomial has $b=-17$ and $c=16$.
Note that $16=(-16)(-1)$ and $-17=(-16)+(-1)$.
This means that $d=-16$ and $e=-1$
Thus, the factored form of the trinomial is:
$=[x+(-16)] [x+(-1)]
\\=(x-16)(x-1)$
