## College Algebra (10th Edition)

(d) $4(x-5)(x+3)$
$4x^2-8x-60$ Factor out a four from all the terms: $4(x^2-2x-15)$ Now factor the terms inside the parentheses by finding two numbers whose product is -15, and sum is -2. These numbers are 3 and -5: $4(x-5)(x+3)$ This is the most complete factorization of $4x^2-8x-60$