College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Factoring Polynomials - R.5 Assess Your Understanding - Page 57: 5


(d) $4(x-5)(x+3)$

Work Step by Step

$4x^2-8x-60$ Factor out a four from all the terms: $4(x^2-2x-15)$ Now factor the terms inside the parentheses by finding two numbers whose product is -15, and sum is -2. These numbers are 3 and -5: $4(x-5)(x+3)$ This is the most complete factorization of $4x^2-8x-60$
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