## College Algebra (10th Edition)

$(2x+3)(4x^2-6x+9)$
$8x^3+27$ To factor the sum of difference of two cubes, let us remember $a^3 + b^3 = (a + b)(a^2 – ab + b^2)$ and $a^3 – b^3 = (a – b)(a^2 + ab + b^2).$ Therefore, when we factor, we get $(2x+3)(4x^2-6x+9).$