Answer
$(-2,0)$ and $(-1.2,1.6) $
Work Step by Step
$\left\{\begin{array}{l}{y=\sqrt{4-x^{2}}}\\{y=2x+4}\end{array}\right.$
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Substitute y into the second equation,
$\begin{aligned}\sqrt{4-x^{2}}&=2x+4\\
4-x^{2}&=4x^{2}+16x+16\\
5x^{2}+16x+12&=0\end{aligned}$
... use the quadratic formula
$x=\displaystyle \frac{-16\pm\sqrt{256-4(5)(12)}}{2(5)}=\frac{-16\pm\sqrt{16}}{10}\\=-1.6\pm 0.4$
$\left[\begin{array}{ll}
x=-2.0 & x=-1.2\\
\text{... back -substitute} & \\
& \\
y=2(-2)+4 & y=2(-1.2)+4\\
y=0 & y=-2.4+4\\
& y=1.6\\
(-2,0) & (-1.2,1.6)\\
&
\end{array}\right]$