Answer
$(0,1)$ and $(1,2)$
Work Step by Step
$\left\{\begin{array}{l}{y=x^{2}+1} \\ {y=x+1}\end{array}\right.$
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Subtracting the equations,
$0=x^{2}+1-x-1$
$0=x^{2}-x$
$0=x(x-1)$
$\left[\begin{array}{lll}
& x=0 & x=1\\
\text{back-substitute: } & y=(0)+1 & y=(1)+1\\
& y=1 & y-2\\
& & \\
& (0,1) & (1,2)\\
& &
\end{array}\right]$