## College Algebra (10th Edition)

$(0,1)$ and $(4,17)$
$\left\{\begin{array}{l}{y=x^{2}+1}\\{y=4x+1}\end{array}\right.$ Graphed with desmos.com/calculator. Subtracting the equations, $0=x^{2}+1-4x-1$ $0=x^{2}-4x$ $0=x(x-4)$ $\left[\begin{array}{lll} & x=0 & x=4\\ \text{back-substitute:} & y=4(0)+1 & y=4(4)+1\\ & y=1 & y-2\\ & & \\ & (0,1) & (4,17)\\ & & \end{array}\right]$