College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Section 8.6 - Systems of Nonlinear Equations - 8.6 Assess Your Understanding - Page 614: 11

Answer

$(0,0)$ and $(8,4)$

Work Step by Step

$\left\{\begin{array}{l}{x=2 y}\\{x=y^{2}-2y}\end{array}\right.$ Graphed with desmos.com/calculator. Substitute $x$ into the second equation, $\begin{aligned}2y&=y^{2}-2y\\0&=y^{2}-4y\\y(y-4)&=0\end{aligned}$ $\left[\begin{array}{ll} y=0 & y=4\\ \text{... back -substitute} & \\ & \\ x=2(0) & x=2(4)\\ x=0 & x=8\\ & \\ (0,0) & (8,4) \\ & \end{array}\right]$
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